Bài 1 :
\(n_{H2}=\dfrac{0,896}{22,4}=0,04\left(mol\right)\)
Pt : \(Zn+2HCl\rightarrow ZnCl_2+H_2|\)
1 2 1 1
0,04 0,08 0,04
a) \(n_{Zn}=\dfrac{0,04.1}{1}=0,04\left(mol\right)\)
⇒ \(m_{Zn}=0,04.65=2,6\left(g\right)\)
b) \(n_{HCl}=\dfrac{0,04.2}{1}=0,08\left(mol\right)\)
⇒ \(m_{HCl}=0,08.36,5=2,92\left(g\right)\)
\(C_{ddHCl}=\dfrac{2,92.100}{200}=1,46\)0/0
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