1. a)PTHH: \(2C_2H_2+5O_2\rightarrow4CO_2+2H_2O\)
b)\(C_2H_2\):\(O_2\)=2:5
\(C_2H_2\):\(CO_2\)=2:4
\(C_2H_2\):\(H_2O\)=2:2
2.a) PTHH:4 Al+3\(O_2\)\(\rightarrow2Al_2O_3\)(1)
2Mg+\(O_2\)\(\rightarrow2MgO\)
b) \(n_{Al}=\dfrac{6,3}{27}=0.233\left(mol\right)\)
nên \(n_{O_2}=\dfrac{0,233.3}{4}=0.175\left(mol\right)\)
suy ra \(m_{O_2}=0,175.32=5.6\left(g\right)\)(PTrinh1)
\(n_{Mg}=\dfrac{6,3}{24}=0,2625\left(mol\right)\)
suy ra \(n_{O_2}=\dfrac{0,2625.1}{2}=0,13125\left(mol\right)\)
\(m_{O_2}=0,13125.32=4.2\left(g\right)\)(Ptrinh2)
khối lượng oxi tham gia là:
5,6+4,2=9,2(g)