Tính giá trị biểu thức A = \(\dfrac{17}{11}-\Big(\dfrac{6}{5}-\dfrac{16}{11}\Big)+\dfrac{26}{5} \).
\(3.\)\(4.\)\(10.\)\(7.\)Hướng dẫn giải:\(A= \dfrac{17}{11}-\Big(\dfrac{6}{5}-\dfrac{16}{11}\Big)+\dfrac{26}{5} \)
\(=\dfrac{17}{11}-\dfrac{6}{5}+\dfrac{16}{11}+\dfrac{26}{5}\)
\(=\Big(\dfrac{17}{11}+\dfrac{16}{11}\Big)+\Big(\dfrac{-6}{5}+\dfrac{26}{5}\Big)\)
\(=3+4\)
\(=7.\)
