Bài 1:

a)25 196:43=585(dư 129)

b)258 109:103=2505(dư 94)

c)161 354x41=6 615 514

d)968 215x504=487 980 360

Bài 2:

\(\dfrac{18}{36}=\dfrac{1}{2}\)

\(\dfrac{153}{30}=\dfrac{51}{10}\)

\(\dfrac{155}{15}=\dfrac{31}{3}\)

\(\dfrac{27}{18}=\dfrac{3}{2}\)

\(\dfrac{63}{18}=\dfrac{7}{2}\)

\(\dfrac{42}{36}=\dfrac{7}{6}\)

\(\dfrac{25}{15}=\dfrac{5}{3}\)

Chúc bn học tốt

chết, em chưa học đến lớp 8 =)

Khó wá và tách ra bn

had said goodbye to her parents, she went to school

I will call the manager who is responsible for this project
so brave of him to run after the thief to get the bag back
that each family needs its own special set of rules and guidelines
I didn't forget telling her the detail about this plan before
If he weren't so lazy, the teacher wouldn't often punish him
Mary said to me that she and John would hold their wedding at the end of that week
You must try your best to keep up with your classmates

\(n_{CaO}=\dfrac{8,4}{56}=0,15\left(mol\right)\)

PTHH: CaCO₃ --t^o--> CaO + CO₂

           0,15<-----------0,15

=> m = 0,15.100 = 15 (g)

h)\(\dfrac{x+2}{x^2+2x+1}\ge0\)

⇔\(\dfrac{x+2}{\left(x+1\right)^2}\ge0\)

⇔\(\dfrac{x+2}{\left(x+1\right)\left(x+1\right)}\ge\dfrac{0.\left(x+1\right)\left(x+1\right)}{\left(x+1\right)\left(x+1\right)}\)

⇒\(x+2\ge0\)

⇔\(x+2-2\ge0-2\)

⇔\(x\ge-2\)

i)\(\dfrac{x-1}{x-3}>1\)

⇔\(\dfrac{x-1}{x-3}>\dfrac{1.\left(x-3\right)}{1.x-3}\)

⇒\(x-1>x-3\)

⇔\(x-x>-3+1\)

⇔\(0x>-2\)

Em xem lại ý nhận biết 3 chất cuối sao đầu CH₂ lại là liên kết 3 được nhỉ

sao nó lại mờ thế?

nhiều thế này ai mà làm nổi

nhỏ xí à

cứu

sos là tín hiệu cầu cứu

cứu