1. 

= 10 000 - 29 x 11

= 10 000 - 319

= 9681

2.

= ( 3/7 + 4/7 ) + ( 4/9 + 5/9 )

= 1 + 1

= 2

5/11.5/7+2/7.5/11

=5/11.(5/7+2/7)

=5/11

15 x 7/15 x 4/9

=7 x 4/9

=28/9

5/11

28/9

( 54 x 15 ) :9

=54:9x15

=90

( 56 x 23 x 4 ) :7

=56:7x23x4

=8x23x4

=32x23

=736

( 54 x 15 ) :9= 90                     ( 56 x 23 x 4 ) :7=736

\(=\dfrac{5}{9}\times\dfrac{7}{4}+\dfrac{13}{9}\times\dfrac{7}{4}=\dfrac{7}{4}\times\left(\dfrac{5}{9}+\dfrac{13}{9}\right)=\dfrac{7}{4}\times2=\dfrac{7}{2}\)

=\(\dfrac{5}{9}\)x\(\dfrac{7}{4}+\dfrac{13}{9}\)x\(\dfrac{7}{4}\)
=\(\dfrac{7}{4}\)x\(\left(\dfrac{5}{9}+\dfrac{13}{9}\right)\)
=\(\dfrac{7}{4}\)x\(2\)
=\(\dfrac{7}{2}\)

5/9 : 4/7 +13/9 *7/4

=(5/9+13/9)* (4/7:7/4)
=2/1+1/1

=3/1

=3

\(=\dfrac{5}{9}\times\dfrac{7}{4}+\dfrac{13}{9}\times\dfrac{7}{4}\\ =\left(\dfrac{5}{9}+\dfrac{13}{9}\right)\times\dfrac{7}{4}\\ =2\times\dfrac{7}{4}\\ =\dfrac{7}{2}\)

`5/9 : 4/7 + 13/9 xx 7/4`

`= 5/9 xx 7/4 + 13/9 xx 7/4`

`= ( 5/9 + 13/9 ) xx 7/4`

`= 18/9 xx 7/4`

`= 2 xx 7/4`

`=7/2` 

\(=\dfrac{5}{9}\times\dfrac{7}{4}+\dfrac{13}{9}\times\dfrac{7}{4}=\dfrac{7}{4}\times\left(\dfrac{5}{9}+\dfrac{13}{9}\right)=\dfrac{7}{4}\times2=\dfrac{14}{4}=\dfrac{7}{2}\)

a) 7/15+14/15+13/15=(7/15+13/15)+14/15=20/15+14/15=34/15
b)13/4+4/9+7/8=(13/4+7/8)+4/9=(26/8+7/8)+4/9=33/8+4/9=297/72+32/72=329/72

a. 7/15 + 14/15 + 13/15

= 7+14+13/ 15

= 34/15

b.13/4 + 4/9 + 7/8

= [ 13/4 + 7/8 ] + 4/9

= [ 26/8  +  7/8 ]  + 4/9

= 33/8  + 4/9

= 297/72  +  32/72

= 329/72

1) Ta có: \(\left(\dfrac{3}{4}\cdot\dfrac{5}{97}+\dfrac{1}{9}\cdot\dfrac{13}{47}\right)\cdot\left(\dfrac{1}{5}-\dfrac{7}{25}\cdot\dfrac{5}{7}\right)\)

\(=\left(\dfrac{3}{4}\cdot\dfrac{5}{97}+\dfrac{1}{9}\cdot\dfrac{13}{47}\right)\cdot\left(\dfrac{1}{5}-\dfrac{1}{5}\right)\)

=0

2) Ta có: \(\dfrac{8}{17}\cdot\dfrac{4}{15}+\dfrac{8}{17}\cdot\dfrac{22}{15}-\dfrac{8}{15}\cdot\dfrac{9}{17}\)

\(=\dfrac{8}{17}\left(\dfrac{4}{15}+\dfrac{22}{15}-\dfrac{9}{15}\right)\)

\(=\dfrac{8}{17}\cdot\dfrac{15}{15}=\dfrac{8}{17}\)

3) Ta có: \(\dfrac{2021}{2}\cdot\dfrac{1}{3}+\dfrac{4042}{4}\cdot\dfrac{1}{5}+\dfrac{6063}{3}\cdot\dfrac{22}{15}\)

\(=\dfrac{2021}{2}\left(\dfrac{1}{3}+\dfrac{1}{5}\right)+2021\cdot\dfrac{22}{15}\)

\(=\dfrac{2021}{2}\cdot\dfrac{8}{15}+\dfrac{2021}{2}\cdot\dfrac{44}{15}\)

\(=\dfrac{2021}{2}\cdot\dfrac{52}{15}\)

\(=\dfrac{52546}{15}\)

4) Ta có: \(\dfrac{4}{7}\cdot\dfrac{2}{13}+\dfrac{8}{13}:\dfrac{7}{4}+\dfrac{4}{7}:\dfrac{13}{2}+\dfrac{4}{7}\cdot\dfrac{1}{13}\)

\(=\dfrac{4}{7}\left(\dfrac{2}{13}+\dfrac{8}{13}+\dfrac{2}{13}+\dfrac{1}{13}\right)\)

\(=\dfrac{4}{7}\)

1) Tính biểu thức:

`a)17/7-3/8+4/7-3/5`

`=(17/7+4/7)-(3/8+3/5)`

`=21/7-(15/40+24/40)=3-39/40=120/40-39/40=81/40`

`b)15/11xx2001/2005-3/11xx2001/2005-1/11xx2001/2005`

`=2001/2005xx(15/11-3/11-1/11)`

`=2001/2005xx11/11`

`=2001/2005`

\(a.60\times\left(\frac{7}{12}+\frac{4}{15}\right)\)

\(=60\times\left(\frac{35}{60}+\frac{16}{60}\right)\)

\(=60\times\frac{51}{60}\)

\(=51\)

\(b.\frac{1}{2}\times\frac{2}{3}\times\frac{3}{4}\times\frac{4}{5}\times\frac{5}{6}\times\frac{6}{7}\times\frac{7}{8}\times\frac{8}{9}\)

\(=\frac{1\times2\times3\times4\times5\times6\times7\times8}{2\times3\times4\times5\times6\times7\times8\times9}\)

\(=\frac{1}{9}\)