2. He asked her where she was going.

3. He asked which way they had gone.

4. I told her to bring it back if it didn't fit.

5. She told us not to try to open it then.

6. I asked her if it was going to be a fine day that day.

7. She said that he was not at home.

8. The girl wanted to know if the bus station was far away.

9. Tom told Ann not to stay out late.

10. He asked her to let him borrow her car.

11. Thomas asked Jean if he had seen his gloves.

12. I told Mary not to leave the window open.

13. She said that she would have a cup of tea with me.

14. She said that she would pay him if she could.

15. She asked what I was going to do the next summer.

Bài 5: 

d: Áp dụng tính chất của dãy tỉ số bằng nhau, ta được:

\(\dfrac{x}{2}=\dfrac{y}{3}=\dfrac{z}{4}=\dfrac{x+y-z}{2+3-4}=\dfrac{-20}{1}=-20\)

Do đó: x=-40; y=-60; z=-80

d nha

D

D

a: BC=căn 6^2+8^2=10cm

bD là phân giác

=>AD/AB=CD/BC

=>AD/3=CD/5=(AD+CD)/(3+5)=8/8=1

=>AD=3cm; CD=5cm

b: Xét ΔBHA vuông tại H và ΔBAC vuông tại A có

góc B chung

=>ΔBHA đồng dạng với ΔBAC

=>BH/BA=BA/BC

=>BH*BC=BA^2

c: Xét ΔBHA có BI là phân giác

nên IH/IA=BH/BA

=>IH/IA=BA/BC=AD/DC

1. Turn on (please+Vo)

2. Turned / off (was chia qk)

3. Look for

4. Got up (because S+ had+V3/ed, S+V2/ed)

5. Ran into( hai hd lien tiep)

6. Goes on (after S+V2/ed, S+Vht)

Em bị deadline dí à :))?? Mấy cái này chỉ cần quy đồng, nhóm hay chuyển vế gì là ra mà, em phải tự làm trước , câu nào không hiểu hay không biết làm thì mới đăng chứ!

Bài 2: 

a) Ta có: \(\dfrac{5}{3}+\dfrac{1}{6}:x=1\)

\(\Leftrightarrow\dfrac{1}{6}:x=\dfrac{2}{3}\)

hay \(x=\dfrac{1}{4}\)

b) Ta có: \(\dfrac{3}{2}-\left|\dfrac{1}{2}x-\dfrac{1}{3}\right|=\dfrac{1}{2}\)

\(\Leftrightarrow\left|\dfrac{1}{2}x-\dfrac{1}{3}\right|=1\)

\(\Leftrightarrow\left[{}\begin{matrix}\dfrac{1}{2}x-\dfrac{1}{3}=1\\\dfrac{1}{2}x-\dfrac{1}{3}=-1\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}\dfrac{1}{2}x=\dfrac{4}{3}\\\dfrac{1}{2}x=-\dfrac{2}{3}\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{8}{3}\\x=-\dfrac{4}{3}\end{matrix}\right.\)

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