Chắc bạn đánh nhầm = thành +
`x+{(x-3)-[(x-3)-(x-2)]}=x`
`=>(x-3)-(x-3-x+2)=x-x`
`=>x-3-(0-1)=0`
`=>x-3-(-1)=0`
`=>x-3+1=0`
`=>x-2=0`
`=>x=2`
Vậy `x=2`
\(x=\left\{\left(x-3\right)-\left[\left(x-3\right)-\left(-x-2\right)\right]\right\}\\ \Rightarrow x=\left[x-3-\left(2x-1\right)\right]\\ \Rightarrow x=x-3-2x+1\\ \Rightarrow x-x+2x=-3+1\\ \Rightarrow2x=-2\\ \Rightarrow x=-1\)
Vậy x = -1