x-32:16=48 \(\Rightarrow\)x-2=48\(\Rightarrow\)x=48+2=50
Vậy x=50
\(x-32\div16=48\)
\(\Rightarrow x-32=48\times16\)
\(\Rightarrow x-32=768\)
\(\Rightarrow x=768+32\)
\(\Rightarrow x=800\)
x - 32 : 16 = 48
=> x - 2 = 48
=> x = 48 + 2
=> x = 50
zZz Ủng hộ nha m.n zZz
x - 32 : 16 = 48
=> x - 2 = 48
=> x = 48 + 2
=> x =50
x - 32 : 16 = 48
x - 32 = 48 x 16
x - 32 = 768
x = 768 + 32
x = 800
Mình nhầm :
\(x-32\div16=48\)
\(\Rightarrow x-2=48\)
\(\Rightarrow x=48+2\)
\(\Rightarrow x=50\)
x - 32 : 16 = 48
=> x - 32 = 48 . 16
=> x - 32 = 768
=> x = 768 + 32
=> x = 800
Vậy x = 800
x - 32 : 16 = 48
x - 32 = 48 x 16
x - 32 = 768
x = 768 + 32
x = 800
x- 32 :16 = 48
x -[32 :16 ] = 48
x - 2 =48 + 2
x =50
x - 32 :16 = 48
x -[32:16 ] = 48
x - 2 =48 +2
x = 50