\(\left|x+\frac{3}{4}\right|-\frac{1}{3}=0\)
\(\Rightarrow\left|x+\frac{3}{4}\right|=\frac{1}{3}\)
\(\Rightarrow\left[\begin{array}{nghiempt}x+\frac{3}{4}=\frac{1}{3}\\x+\frac{3}{4}=-\frac{1}{3}\end{array}\right.\)
\(\Rightarrow\left[\begin{array}{nghiempt}x=\frac{1}{3}-\frac{3}{4}\\x=-\frac{1}{3}-\frac{3}{4}\end{array}\right.\)
\(\Rightarrow\left[\begin{array}{nghiempt}x=-\frac{5}{12}\\x=-\frac{13}{12}\end{array}\right.\)
Vậy \(\left[\begin{array}{nghiempt}x=-\frac{5}{12}\\x=-\frac{13}{12}\end{array}\right.\)
\(\text{|x-1,7|=2,3}\)
\(\Rightarrow\left[\begin{array}{nghiempt}x-1,7=2,3\\x-1,7=-2,3\end{array}\right.\)
\(\Rightarrow\left[\begin{array}{nghiempt}x=2,3+1,7\\x=-2,3+1,7\end{array}\right.\)
\(\Rightarrow\left[\begin{array}{nghiempt}x=4\\x=-0,6\end{array}\right.\)
Vậy \(\left[\begin{array}{nghiempt}x=4\\x=-0,6\end{array}\right.\)
\(\left|x+\frac{1}{3}\right|-\left(-4\right)=-1\)
\(\Rightarrow\left|x+\frac{1}{3}\right|=-1+\left(-4\right)\)
\(\Rightarrow\left|x+\frac{1}{3}\right|=-5\) (vô lí vì \(\left|x+\frac{1}{3}\right|\ge0\forall x\))
=> Không có giá trị x thỏa mãn.
Vậy không có giá trị x thỏa mãn
Mình làm tách từng phần ra cho đỡ rối nhé!