Ta có: \(\left(x-1\right)^2+x\left(4-x\right)=0\)
\(\Leftrightarrow x^2-2x+1+4x-x^2=0\)
\(\Leftrightarrow2x+1=0\)
\(\Leftrightarrow2x=-1\)
hay \(x=-\dfrac{1}{2}\)
Vậy: \(x=-\dfrac{1}{2}\)
b. x( x – 4) - 2x + 8 = 0
c. x^2-25 –( x+5 ) = 0
d.(2x -1)^2- (4x2 – 1) = 0
e. ( 3x – 1)^2 – ( x +5)^2 = 0
f. x^3 – 8 – (x -2)(x -12) =0
Tìm x
Bài 1
1.(x-3)(x+2)-x(x-7)=15
2.(x-5)(x+5)+x(3-x)=20
3.(x-7)2-x(2+x)=-7
4.(x-4)2-(x+4)(x-4)=-16
5.(x-5)(x+5)-x(2-3x)=4x2-7
Bai2
1.2x(x-2)+3x-6=0
2.3x(x-5)-5x+25=0
3.x(x+7)-x-7=0
4.(5x-20)+3x2-12x=0
5.(1-x)-3x2+3x=0
Bài 3
1.(x-1)(x+2)+5x-5=0
2.(3x+5)(x-3)-6x-10=0
3.(x-2)(2x+3)-7x2+14x=0
4.(x+1)(x-3)-15+5x=0
5.5(2x-1)(x+3)+5x-10x2=0
Bài4
1.3x-6+(x+1)(x-2)=0
2.4x2+6x-(2x+3)(3x-x)=0
3.5x-10-(2-x)(4+x)=0
4.10-10x+(x-1)(x-3)=0
5.20x2+30x-2(x-5)(2x+3)=0
19 Tìm x, biết
a) (x+2)(x+3)-(x-2)(x+5)=0 ; b) (2x+3)(x-4)+(x-5)(x-2)=(3x-5)(x-4)
c) (8-4x)(x+2)+4(x-2)(x+1)=0 ; d) (2x-3)(8x+2)=(4x+1)(4x-1)-3
a) x2(x - 5) + 5 - x = 0; b) 3x4 - 9x3 = -9x2 + 27x;
c) x2(x + 8) + x2 = -8x; d) (x + 3)(x2 -3x + 5) = x2 + 3x.
e) 3x(x - 1) + x - 1 = 0;
f) (x - 2)(x2 + 2x + 7) + 2(x2 - 4) - 5(x - 2) = 0;
g) (2x - 1)2 - 25 = 0;
h) x3 + 27 + (x + 3)(x - 9) = 0.
i)8x3 - 50x = 0; k) 2(x + 3)-x2 - 3x = 0;
m)6x2 - 15x - (2x - 5)(2x + 5) =
Tìm x:
a) (x-20) mũ 2 -(x+1)(x+3)=-7
b) (3x+5)(4-3x)=0
c) x mũ 3 -9x=0
d)2/3x (x mũ 2 -4)=0
e) (2x+1)-x(2x+1)=0
f)(2x-1) mũ 2 -(2x+5) (2x-5) =18
g)x mũ 2 -25 =6x-9
Bài 1:
a) 2/3.x.(x2-4)= 0
b)(x+2)2-(x-2).(x+2)=0
c)x2+2x+1=0
1)(x+4)(x-4)+x(6-x)=0 2)(x-3)lũy thừa 2=9-lũy thừa 2
Đề: Tìm x
a)2x.(3x+5)-x.(6x-1)=33 k)5(x+3)-2x(x+3)=0
b)x(3x-1)+12x-4=0 i)5x(x-2)-(2-x)=0
c)5x(2x+1)-12x-6=0 m)x(x-1)-2(1-x)=0
d)x3-5x2+4x-20=0
e)2x3-5x2+2x-5=0
g)(x-2)3-x(x+1).(x-1)+62=5
tìm x
a)1/2x. (x^2 - 4) = 0
b) (x+2 )^2 - ( x- 2) (x+ 2) = 0
