Câu hỏi của nguyen ngoc linh a

Question

tinh giá trị biểu thức x=2;y=-2

M=x(x2-y)(x3-2y2)(x4-3y3)(x5-4y4)

Iravy Daisy · Accepted Answer

$M=x\left(x^2-y\right)\left(x^3-2y^2\right)\left(x^4-3y^3\right)\left(x^5-4y^4\right)$

$M=x\left(x^2-y\right)\left(2^3-2\left(-2\right)^2\right)\left(x^4-3y^3\right)\left(x^5-4y^4\right)$

$M=x\left(x^2-y\right)\left(8-2\cdot4\right)\left(x^4-3y^3\right)\left(x^5-4y^4\right)$

$M=x\left(x^2-y\right)\left(8-8\right)\left(x^4-3y^3\right)\left(x^5-4y^4\right)$

$M=x\left(x^2-y\right)\cdot0\cdot\left(x^4-3y^3\right)\left(x^5-4y^4\right)$

⇒$M=0$Câu trả lời: $M=x\left(x^2-y\right)\left(x^3-2y^2\right)\left(x^4-3y^3\right)\left(x^5-4y^4\right)$

$M=x\left(x^2-y\right)\left(2^3-2\left(-2\right)^2\right)\left(x^4-3y^3\right)\left(x^5-4y^4\right)$

$M=x\left(x^2-y\right)\left(8-2\cdot4\right)\left(x^4-3y^3\right)\left(x^5-4y^4\right)$

$M=x\left(x^2-y\right)\left(8-8\right)\left(x^4-3y^3\right)\left(x^5-4y^4\right)$

$M=x\left(x^2-y\right)\cdot0\cdot\left(x^4-3y^3\right)\left(x^5-4y^4\right)$

⇒$M=0$

caikeo · Answer

M=x(x2−y)(x3−2y2)(x4−3y3)(x5−4y4)M=x(x2−y)(x3−2y2)(x4−3y3)(x5−4y4)

M=x(x2−y)(23−2(−2)2)(x4−3y3)(x5−4y4)M=x(x2−y)(23−2(−2)2)(x4−3y3)(x5−4y4)

M=x(x2−y)(8−2⋅4)(x4−3y3)(x5−4y4)M=x(x2−y)(8−2⋅4)(x4−3y3)(x5−4y4)

M=x(x2−y)(8−8)(x4−3y3)(x5−4y4)M=x(x2−y)(8−8)(x4−3y3)(x5−4y4)

M=x(x2−y)⋅0⋅(x4−3y3)(x5−4y4)M=x(x2−y)⋅0⋅(x4−3y3)(x5−4y4)

⇒M=0M=0

Đúng 1  Bình luận  Báo cáo sai phạmCâu trả lời: M=x(x2−y)(x3−2y2)(x4−3y3)(x5−4y4)M=x(x2−y)(x3−2y2)(x4−3y3)(x5−4y4)

M=x(x2−y)(23−2(−2)2)(x4−3y3)(x5−4y4)M=x(x2−y)(23−2(−2)2)(x4−3y3)(x5−4y4)

M=x(x2−y)(8−2⋅4)(x4−3y3)(x5−4y4)M=x(x2−y)(8−2⋅4)(x4−3y3)(x5−4y4)

M=x(x2−y)(8−8)(x4−3y3)(x5−4y4)M=x(x2−y)(8−8)(x4−3y3)(x5−4y4)

M=x(x2−y)⋅0⋅(x4−3y3)(x5−4y4)M=x(x2−y)⋅0⋅(x4−3y3)(x5−4y4)

⇒M=0M=0

Đúng 1  Bình luận  Báo cáo sai phạm

Bài 2: Giá trị của một biểu thức đại số