Question

Tính

\(\dfrac{2^8.52+2^{10}.65}{2^8.104}\)

Answer 1

\(\dfrac{2^8.52+2^{10}.65}{2^8.104}\)

\(=\dfrac{2^8.2^2.13+2^{10}.13.5}{2^8.2^3.13}\)

\(=\dfrac{2^{10}.13+2^{10}.13.5}{2^{11}.13}\)

\(=\dfrac{2^{10}.13.\left(5+1\right)}{2^{11}.13}\)

\(=\dfrac{2^{10}.13.6}{2^{11}.13}\)

\(=\dfrac{2^{11}.13.3}{2^{11}.13}=3\)

Answer 2

\(\dfrac{2^8.52+2^{10}.65}{2^8.104}=\dfrac{2^8.4.13+2^{10}.65}{2^8.4.13.2}=\dfrac{2^{10}.13+2^{10}.65}{2^{10}.13.2}=\dfrac{2^{10}.\left(13+65\right)}{2^{10}.13.2}=\dfrac{2^{10}.78}{2^{10}.13.2}=\dfrac{2^{10}.2.13.3}{2^{10}.13.2}=3\)

Answer 3

=\(\dfrac{2^8.2^2.13+2^{10}.5.13}{2^8.2^3.13}=\dfrac{2^{10}.13+2^{10}.5.13}{2^{10}.13.2}=\dfrac{2^{10}.13.\left(1+6\right)}{2^{10}.13.2}=\dfrac{7}{2}\)