Question

Tính :

a) \(\left(-38\right)+28\)

b) \(272+\left(-123\right)\)

c) \(99+\left(-100\right)+101\)

Answer 1

a)(-38) + 28= -( \(\left|-38\right|\) - \(\left|28\right|\)) = - (38-28)= - 10

b) 272+ (-123)= (\(\left|272\right|\) - \(\left|-123\right|\) ) = 272- 123= 149

c) 99+(-100)+101= -( 100-99) +101= -1+ 101=100

Answer 2

a) (-38)+28 = -(38-28)= -10

b) 272 + (-273)= -(273-272)= -1

c) 99+ (-100)+ 101= (99+101)-100= 200-100= 100