Question

Tính

\(A=-\dfrac{11}{12}\cdot-\dfrac{4}{33}\cdot\dfrac{84}{-25}\cdot\dfrac{5}{8}\)

\(B=3\dfrac{2}{7}\cdot12\dfrac{2}{7}-3\dfrac{2}{7}\cdot5\dfrac{1}{2}\)

Answer 1

\(A=\dfrac{-11}{12}.\dfrac{-4}{33}.\dfrac{84}{-25}.\dfrac{5}{8}\)

\(A=\dfrac{1}{9}.\dfrac{-21}{10}\)

\(A=\dfrac{-7}{30}\)

\(B=3\dfrac{2}{7}.12\dfrac{2}{7}-3\dfrac{2}{7}.5\dfrac{1}{2}\)

\(B=\dfrac{23}{7}.\dfrac{86}{7}-\dfrac{23}{7}.\dfrac{11}{2}\)

\(B=\dfrac{23}{7}.\left(\dfrac{86}{7}-\dfrac{11}{2}\right)\)

\(B=\dfrac{23}{7}.\dfrac{95}{14}\)

\(B=\dfrac{2185}{98}\)

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