\(73-3\left|x+2\right|=-47\)
th1: \(x+2\ge0\Leftrightarrow x\ge-2\)
\(\Rightarrow73-3\left|x+2\right|=-47\Leftrightarrow73-3\left(x+2\right)=-47\)
\(\Leftrightarrow73-3x-6=-47\Leftrightarrow-3x=-47-73+6=-114\)
\(\Leftrightarrow x=\dfrac{-114}{-3}=38\left(tmđk\right)\)
th2: \(x+2< 0\Leftrightarrow x< -2\)
\(\Rightarrow73-3\left|x+2\right|=-47\Leftrightarrow73-3\left(-x-2\right)=-47\)
\(\Leftrightarrow73+3x+6=-47\Leftrightarrow3x=-47-73-6=126\)
\(\Leftrightarrow x=\dfrac{126}{3}=-42\left(tmđk\right)\)
vậy \(x=38;x=-42\)
\(73-3\left|x+2\right|=-47\)
\(3\left|x+2\right|=73-\left(-47\right)\)
\(3\left|x+2\right|=120\)
\(\left|x+2\right|=40\)
\(\Rightarrow\left[{}\begin{matrix}x+2=40\\x+2=-40\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=38\\x=-42\end{matrix}\right.\)