Ta có:
\(\frac{5^5.20^4}{25^5.4^5}=\frac{5^5.5^4.4^4}{5^{10}.4^5}=\frac{5^9.4^4}{5^{10}.4^5}=\frac{1}{5.4}=\frac{1}{20}\)
\(\frac{5^5.20^4}{25^5.4^5}=\frac{5^5.\left(5.2^2\right)^4}{\left(5^2\right)^5.\left(2^2\right)^5}=\frac{5^5.5^4.2^8}{5^{10}.2^{10}}=\frac{5^9.2^8}{5^{10}.2^{10}}=\frac{1}{5.2^2}=\frac{1}{5.4}=\frac{1}{20}.\)
Chúc bạn học tốt!
8^20+4^20/4^25+64^5
8^20+4^20\4^25+64^5
a,\(\dfrac{8^{20}+4^{20}}{4^{25}+64^5}\)
b,\(\left(1+\dfrac{2}{3}-\dfrac{1}{4}\right).\left(\dfrac{4}{5}-\dfrac{3}{4}\right)^2\)
c,\(23\dfrac{1}{3}:\left(\dfrac{-5}{7}\right)-13\dfrac{1}{3}:\left(\dfrac{-5}{7}\right)\)
d,1:\(\left(\dfrac{2}{3}-\dfrac{3}{4}\right)^2\)
e,\(\dfrac{45^{10}.5^{20}}{75^{15}}\)
Tính
\(\frac{8^{20}+4^{20}}{4^{25}+64^5}\)
\(\dfrac{2^{12}\cdot3^5-4^6\cdot9^2}{\left(2^3\cdot3\right)+8^4\cdot3^5}-\dfrac{5^{10}\cdot7^3-25^5\cdot49^2}{\left(125\cdot7\right)^3+5^9\cdot14^3}\) .Tính tổng
Sai nát nhất ở đâu trong bài toán dưới :
Chứng minh:4 = 5
-->Ta có
-20 = -20
<=> 25 - 45 = 16 - 36
=> 5^2 - 2.5.9/ 2 = 4^2 - 2.4.9/2
Cộg cả 2 vế với (9/2)^2 để xuất hiện hằg đẳg thức :
5^2 - 2.5.9/2 + (9/2)^2 = 4^2 - 2.4.9/2 + (9/2)^2
<=> (5 - 9/2)^2 = (4 - 9/2 )^2
=> 5 - 9/2 = 4 - 9/2
=> 5 = 4
m=-1,2:(1/1/5.1,25)/0.64-1/25+(1,08-1/25):4/7/(5/5/9-9/4).36/17 +0,6.0.5;2/5
m=(-1,2:(1 3/5x1,25) / 0,64 -1/25) +((1,08-2/25):4/ 7 /(5 5/9-9/4)x36/17)+0,6x0,5 :2/5
Tính :
a)\(\dfrac{8^{20}.4^{10}}{16^{21}}\)
b)\(\dfrac{8^{20}+4^{20}}{4^{25}+64^5}\)
