\(3\frac{1}{4}+\left(-5\right).\frac{1}{5}-\left(-7\frac{3}{4}\right)=\frac{13}{4}-1+\frac{31}{4}=\frac{13-4+31}{4}=\frac{40}{4}=10\)
Xin giải giúp:
1. \(\left(x-\frac{5}{24}\right)\frac{18}{7}=-\frac{12}{7}\)
2. \(\frac{3}{4}+\frac{1}{4}\left(x-1\right)=\frac{1}{2}\)
3. \(\left(4x-\frac{1}{2}\right)\left(\frac{x}{3}-\frac{1}{5}\right)=0\)
Cảm ơn nhiều!!
a) \(1-\left(5\frac{3}{8}+x-7\frac{5}{24}\right):\left(-16\frac{2}{3}\right)=0\)
b) \(\left(\frac{x}{3}-5\frac{1}{4}\right)^2-\frac{-2}{5}=1\frac{1}{25}\)
c) \(\frac{17-x}{12}=\frac{3}{17-x}\)
d) \(1\frac{1}{3}-25\%\left(x-\frac{8}{3}\right)+2x=1,6:\frac{3}{5}\)
bài 1
a, \(\frac{-3}{7}\)-\(\left\{\frac{2}{3}-\frac{3}{7}\right\}\) b,\(\frac{2}{15}:\left[\frac{1}{3}.\frac{4}{5}-\frac{1}{3}.\frac{6}{5}\right]\)
Tìm x
a)\(5\frac{8}{17}:x+\left(-\frac{4}{7}\right)+3\frac{1}{7}:17\frac{1}{3}=\frac{4}{11}\)
b) \(\left(x+\frac{1}{5}\right)^2+\frac{17}{25}=\frac{26}{25}\)
1. tính nhanh
a) \(15\frac{3}{13}-\left(3\frac{4}{7}+8\frac{3}{13}\right)\)
b) \(\left(7\frac{4}{9}+4\frac{7}{11}\right)-3\frac{1}{2}\)
c) \(\frac{-7}{9}\times\frac{4}{11}+\frac{-7}{9}\times\frac{7}{11}+5\frac{7}{9}\)
1/ \(\left(\frac{7}{8}-\frac{3}{4}\right).1\frac{1}{3}-\frac{2}{7}.\left(3,5\right)^2\)
2/\(1,25:\left(10,3-9,8\right)-\frac{3}{4}\)
Thực hiện phép tính
\(a,(\frac{-5}{28}+1,75+\frac{8}{35}).(-3\frac{9}{20})\) \(b,(6-2\frac{4}{5}).3\frac{1}{8}-1\frac{3}{5}:\frac{1}{4}\)
\(c,(\frac{7-5}{24}+0,75+\frac{7}{12}):(-2\frac{1}{8})\) \(d,8\frac{2}{7}-(3\frac{4}{7}+4\frac{2}{7})\)
\(e,\left(-3,2\right).\frac{-15}{64}+(0,8-2\frac{4}{15}):3\frac{2}{3}\) \(f,1\frac{13}{15}.\left(0,5\right)^2.3+(\frac{8}{15}-1\frac{19}{60}):1\frac{23}{24}\)
\(g,1,4.\frac{15}{49}-(\frac{4}{5}+\frac{2}{3}):2\frac{1}{5}\)
tìm x biết
a)
\(\frac{1}{2}\)+\(\frac{2}{3}\).x=\(\frac{4}{5}\)
b)
x+\(\frac{1}{4}\)=\(\frac{4}{3}\)|
c)
\(\frac{3}{5}x-\frac{1}{2}=-\frac{1}{7}\)
|d)
\(\left|x+5\right|-6=9\)
e)
\(\left|x-\frac{4}{5}\right|=\frac{3}{4}\)
f)
\(\frac{1}{2}-\left|x\right|=\frac{1}{3}\)
g)
\(^{x^2}\)=16
h)
\(\left(x-\frac{1}{2}\right)^3=\frac{1}{27}\)
i)
\(^{3^3}\).x=\(^{3^6}\)
j)
\(\frac{1,35}{0,2}=\frac{1,25}{x}\)
k)
\(1\frac{2}{3}:x=6:0,3\)
tìm x biết \(\frac{2}{3}x:\frac{1}{5}=1\frac{1}{5}:25\%\)
Tìm x\(\varepsilon\)biết \(\frac{4}{3}.\left(\frac{1}{6}-\frac{1}{2}\right)\)<x<\(\frac{2}{3}\).\(\left(\frac{-1}{6}+\frac{3}{4}\right)\)