Bài 1: Nguyên hàm

H24

Tìm:

a) \(\int\left(2x^5+3\right)dx;\)             b) \(\int\left(5\cos x-3\sin x\right)dx;\)           c) \(\int\left(\dfrac{\sqrt{x}}{2}-\dfrac{2}{x}\right)dx\);             d) \(\int\left(e^{x-2}-\dfrac{2}{\sin^2x}\right)dx.\)

H24
29 tháng 10 2024 lúc 22:57

a) \(\int {\left( {2{x^5} + 3} \right)dx}  = 2\int {{x^5}dx}  + 3\int {dx}  = 2\frac{{{x^6}}}{6} + 3x + C = \frac{{{x^6}}}{3} + 3x + C\)

b) \(\int {\left( {5\cos x - 3\sin x} \right)dx}  = 5\int {\cos xdx}  - 3\int {\sin xdx}  = 5\sin x - 3\left( { - \cos x} \right) + C\)

\( = 5\sin x + 3\cos x + C\)

c) \(\int {\left( {\frac{{\sqrt x }}{2} - \frac{2}{x}} \right)dx}  = \frac{1}{2}\int {{x^{\frac{1}{2}}}dx}  - 2\int {\frac{1}{x}dx}  = \frac{1}{2}.\frac{{{x^{\frac{3}{2}}}}}{{\frac{3}{2}}} - 2\ln \left| x \right| + C = \frac{1}{3}\sqrt {{x^3}}  - 2\ln \left| x \right| + C\)

d) \(\int {\left( {{e^{x - 2}} - \frac{2}{{{{\sin }^2}x}}} \right)dx}  = {e^{ - 2}}\int {{e^x}dx}  - 2\int {\frac{1}{{{{\sin }^2}x}}dx = {e^{ - 2}}.{e^x} - 2\left( { - \cot x} \right) + C} \) \( = {e^{x - 2}} + 2\cot x + C\)

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