Question

Tìm x;y biết: x(x-y)=3/10 ; y(x-y)=-3/50

Answer 1

ta có : x(x-y)-y(x-y) = \(\dfrac{3}{10}+\dfrac{3}{50}\)

=> (x-y)(x-y) = \(\dfrac{9}{25}\)

=> \(\left(x-y\right)^2\) = \(\dfrac{9}{25}\)

=> \(\left[{}\begin{matrix}x-y=\dfrac{3}{5}\\x-y=\dfrac{-3}{5}\end{matrix}\right.\)

=> \(\left[{}\begin{matrix}x=\dfrac{1}{2};y=\dfrac{-1}{10}\\x=\dfrac{-1}{2};y=\dfrac{1}{10}\end{matrix}\right.\)

Vậy \(\left[{}\begin{matrix}x=\dfrac{1}{2};y=\dfrac{-1}{10}\\x=\dfrac{-1}{2};y=\dfrac{1}{10}\end{matrix}\right.\)

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