Question

tìm x,y biết:

| x+5 | +(3y-4)²⁰¹² =0

Answer 1

Ta có :

\(\left|x+5\right|+\left(3y-4\right)^{2012}=0\)

\(\Leftrightarrow\)\(\left\{{}\begin{matrix}\left|x+5\right|=0\\\left(3y-4\right)^{2012}=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x+5=0\\3y-4=0\end{matrix}\right.\)

\(\Leftrightarrow\)\(\left\{{}\begin{matrix}x=-5\\3y=4\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=-5\\y=\dfrac{4}{3}\end{matrix}\right.\)

Vậy \(x=-5\) và \(y=\dfrac{4}{3}\)

Chúc bạn học tốt ~