Giải:
a) Để:
\(x+22⋮x+1\)
\(\Leftrightarrow x+1+21⋮x+1\)
\(\Leftrightarrow21⋮x+1\)
\(\Leftrightarrow x+1\inƯ\left(21\right)=\left\{\pm1;\pm3;\pm7;\pm21\right\}\)
\(\Leftrightarrow x=\left\{-2;0;-4;2;-8;6;-22;20\right\}\)
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b) \(\left(x-2\right)\left(2y+1\right)=17\)
Ta có bảng:
x - 2 | 1 | -1 | 17 | -17 |
2y + 1 | -1 | 1 | -17 | 17 |
x | 3 | 1 | 19 | -15 |
y | -1 | 0 | -9 | 8 |
Vậy ...