\(\left|x-3\right|+x=3\)
\(\Rightarrow\left|x-3\right|=3-x\)
\(\Rightarrow x-3=\pm\left(3-x\right)\)
+) \(x-3=3-x\)
\(\Rightarrow x+x=3+3\)
\(\Rightarrow x=3\)
+) \(x-3=-\left(3-x\right)\)
\(\Rightarrow x-3=-3+x\)
\(\Rightarrow x-x=-3+3\)
\(\Rightarrow0=0\) ( không có giá trị x )
Vậy x = 3
/x+3/+x=3<=>/x+3/=3-x<=>\(\left[\begin{array}{nghiempt}x+3=3-x\\x+3=-\left(3-x\right)\end{array}\right.\)<=>\(\left[\begin{array}{nghiempt}x=0\\x=0\end{array}\right.\)
Vậy x=0