f) \(\dfrac{1}{4}+\dfrac{1}{3}:3x=-5\)
\(\Rightarrow\dfrac{1}{4}+\dfrac{1}{3}\cdot\dfrac{1}{3}x=-5\)
\(\Leftrightarrow\dfrac{1}{4}+\dfrac{1}{9}x=-5\)
\(\Leftrightarrow9+4x=-180\)
\(\Leftrightarrow4x=-180-9\)
\(\Leftrightarrow4x=-189\)
\(\Rightarrow x=-\dfrac{189}{4}\)
a)\(\dfrac{1}{4}+\dfrac{1}{3}:3x=-5\)
\(\Rightarrow\dfrac{1}{4}+\dfrac{1}{3}\cdot\dfrac{1}{3}x=-5\)
\(\Rightarrow\dfrac{1}{4}+\dfrac{1}{9}x=-5\)
\(\Rightarrow\dfrac{1}{9}x=-5-\dfrac{1}{4}\)
\(\Rightarrow\dfrac{1}{9}x=\dfrac{-21}{4}\)
\(\Rightarrow x=\dfrac{-21}{4}:\dfrac{1}{9}\)
\(\Rightarrow x=\dfrac{-189}{4}\)
Vậy \(x=\dfrac{-189}{4}\).
b)\(1-\left(\dfrac{5}{\dfrac{3}{8}}+x-\dfrac{7}{\dfrac{5}{24}}\right):\left(\dfrac{-16}{\dfrac{2}{3}}\right)=0\)
\(\Rightarrow1-\left(\dfrac{40}{3}+x-\dfrac{168}{5}\right):\left(-24\right)=0\)
\(\Rightarrow1-\left(\dfrac{-304}{15}+x\right):\left(-24\right)=0\)
\(\Rightarrow\left(\dfrac{-304}{15}+x\right):\left(-24\right)=1\)
\(\Rightarrow\dfrac{-304}{15}+x=1\cdot\left(-24\right)\)
\(\Rightarrow\dfrac{-304}{15}+x=-24\)
\(\Rightarrow x=-24-\dfrac{-304}{15}\)
\(\Rightarrow x=\dfrac{-56}{15}\)
Vậy \(x=\dfrac{-56}{15}\).
f, \(\dfrac{1}{4}+\dfrac{1}{3}:3x=-5\)
\(\Rightarrow\dfrac{1}{4}+\dfrac{1}{3}.\dfrac{1}{3}x=-5\)
\(\Rightarrow\dfrac{1}{4}+\dfrac{1}{9}x=-5\)
\(\Rightarrow\dfrac{1}{9}x=-5-\dfrac{1}{4}\)
\(\Rightarrow\dfrac{1}{9}x=\dfrac{-21}{4}\)
\(\Rightarrow x=\dfrac{-21}{4}.9\)
\(\Rightarrow x=\dfrac{-189}{4}\)