Question

tim x : \(\dfrac{3}{7}\).5 - 9 = \(\dfrac{3x+57}{x}\)+ 161\(\dfrac{1}{7}\)

Answer 1

Tìm x :

\(\dfrac{3}{7}\) . 5 - 9 = \(\dfrac{3\text{x}+57}{x}\) + 161\(\dfrac{1}{7}\)

\(\dfrac{15}{7}\) - 9 = \(\dfrac{3\text{x}}{x}\) + \(\dfrac{57}{x}\) + \(161\dfrac{1}{7}\)

\(\dfrac{15}{7}\) - 9 = 3 + 57 : x + 161\(\dfrac{1}{7}\)

\(\dfrac{-48}{7}\) = \(164\dfrac{1}{7}\) + 57 : x

=> 164\(\dfrac{1}{7}\) + 57 : x = \(\dfrac{-48}{7}\)

=> 57 : x = \(\dfrac{-48}{7}\) - 164\(\dfrac{1}{7}\)

=> 57 : x = -171

=> x = -171 . 57

=> x = -9747

Vậy : x = -9747