Question

Tìm x biết

(x+\(\frac{1}{2}\))⁴ =16

Kiểm tra dùm coi mik làm đúng ko na

Answer 1

\(\left(x+\frac{1}{2}\right)^4=16\)

\(\Rightarrow\left[\begin{array}{nghiempt}\left(x+\frac{1}{2}\right)^4=2^4\\\left(x+\frac{1}{2}\right)^4=-2^4\end{array}\right.\)

\(\Rightarrow\left[\begin{array}{nghiempt}x+\frac{1}{2}=2\\x+\frac{1}{2}=-2\end{array}\right.\)

\(\Rightarrow\left[\begin{array}{nghiempt}x=2-\frac{1}{2}\\x=-2-\frac{1}{2}\end{array}\right.\)

\(\Rightarrow\left[\begin{array}{nghiempt}x=\frac{3}{2}\\x=-\frac{5}{2}\end{array}\right.\)

Answer 2

             ( x + \(\frac{1}{2}\) )⁴ = 16

              Vì 2⁴ = 16 \(\Rightarrow\)x + \(\frac{1}{2}\) = 2

                                     x = 2 - \(\frac{1}{2}\)

                                      x = \(\frac{3}{2}\)

Answer 3

\(\left(x+\frac{1}{4}\right)^4=16\)

\(\Rightarrow\left[\begin{array}{nghiempt}\left(x+\frac{1}{4}\right)^4=2^4\\\left(x+\frac{1}{4}\right)^4=-2^4\end{array}\right.\)

\(\Rightarrow\left[\begin{array}{nghiempt}x+\frac{1}{4}=2\\x+\frac{1}{4}=-2\end{array}\right.\)

\(\Rightarrow\left[\begin{array}{nghiempt}x=2-\frac{1}{4}\\x=-2-\frac{1}{4}\end{array}\right.\)

\(\Rightarrow\left[\begin{array}{nghiempt}x=\frac{7}{4}\\x=-\frac{9}{4}\end{array}\right.\)

Answer 4

\(\left(x+\frac{1}{2}\right)^4=16\)

\(\left(x+\frac{1}{2}\right)^4=\sqrt[4]{16}\)

\(\left(x+\frac{1}{2}\right)=2\)

  \(x=2-\frac{1}{2}\)

  \(x=\frac{3}{2}\)

Answer 5

ủa nhầm

Answer 6

để sửa

Answer 7

Ai mới đúng j

Answer 8

@Lê Nguyên Hạo đúng đấy 

- Do ⁴ là số chẵn nên phải có 2 trường hợp xảy ra 

Answer 9

X = 3/2