\(x-\dfrac{3}{4}.x+\dfrac{1}{2}=0\)
\(4x-3x+2=0\)
\(x+2=0\Rightarrow x=-2\)
\(x-\dfrac{3}{4}.x+\dfrac{1}{2}=0\)
= \(x.\left(1-\dfrac{3}{4}\right)\)= \(0-\dfrac{1}{2}\)
= \(x.\dfrac{1}{4}=\dfrac{-1}{2}\)
\(x=\dfrac{-1}{2}:\dfrac{1}{4}\)
\(x=-2\)