Tích cho mình nha, làm đúng đó
|x-2| -|2x+3| =-2+x
Nếu x-2 =0 ---> x=2
2x+3=0---->x=\(\dfrac{-3}{2}\)
Ta có bảng xét dấu :
| 2 | \(\dfrac{-3}{2}\) | |||
| x-2 | - | 0 | + | + |
| 2x+3 | - | - | 0 + |
Th1 : Nếu x <= 2 thì -x+2+2x+3 = -2+x
-x+2x-x = -2-2-3
0x=7 (sai)
TH2: Nếu 2 <=x< \(\dfrac{-3}{2}\)thì x-2+2x+3 = -2+x
x+2x-x = -2+2-3
2x=-3
x=\(\dfrac{-3}{2}\) (L)
Th3 : Nếu x>= \(\dfrac{-3}{2}\) thì x-2 -2x-3 = -2+x
x-2x-x = -2+2+3
-2x=3
x=\(\dfrac{-3}{2}\) (t/m)
Vậy x>= \(\dfrac{-3}{2}\)