Question

Tìm x biết

\(\dfrac{x+2}{327}+\dfrac{x+3}{326}+\dfrac{x+4}{325}+...+\dfrac{x+349}{5}=0\)

Answer 1

\(\dfrac{x+2}{327}+\dfrac{x+3}{326}+\dfrac{x+4}{325}+...+\dfrac{x+349}{5}=0\) (Có (349-2)+1=348 số hạng )

\(\Rightarrow\left(\dfrac{x+2}{327}+1\right)+\left(\dfrac{x+3}{326}+1\right)+\left(\dfrac{x+4}{325}+1\right)+....+\left(\dfrac{x+349}{5}\right)=348\)

\(\Rightarrow\left(\dfrac{x+2}{327}+\dfrac{327}{327}\right)+\left(\dfrac{x+3}{326}+\dfrac{326}{326}\right)+\left(\dfrac{x+4}{325}+1\right)+...+\left(\dfrac{x+349}{5}+\dfrac{5}{5}\right)=348\)

\(\Rightarrow\dfrac{x+329}{327}+\dfrac{x+329}{326}+\dfrac{x+329}{325}+...+\dfrac{x+329}{5}=348\)

\(\Rightarrow\left(x+329\right).\left(\dfrac{1}{327}+\dfrac{1}{326}+\dfrac{1}{325}+...+\dfrac{1}{5}\right)=348\)

Bạn tự làm nốt nha