\(\Leftrightarrow\dfrac{3\left(x+2\right)}{\left(x-5\right)\left(x+2\right)}=\dfrac{-4\left(x-5\right)}{\left(x+2\right)\left(x-5\right)}\)
\(\Leftrightarrow\dfrac{3x+6}{\left(x-5\right)\left(x+2\right)}=\dfrac{-4x+20}{\left(x+2\right)\left(x-5\right)}\)
\(\Rightarrow3x+6=-4x+20\)
\(\Leftrightarrow3x+4x=20-6\)
\(\Leftrightarrow7x=14\)
\(\Leftrightarrow x=2\)
Vậy x= 2