\(\frac{2x+3}{7}=\frac{4x-1}{15}\\ \Rightarrow15\left(2x+3\right)=7\left(4x-1\right)\\ \Rightarrow30x+45=28x-7\\ \Rightarrow2x=-52\\ \Rightarrow x=-26\)
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Có \(\frac{2x+3}{7}=\frac{4x-1}{15}\)
=>\(15\left(2x+3\right)=7\left(4x-1\right)\)
\(30x+45=28x-7\)
\(30x-28x=\left(-7\right)-45\)
\(2x=-52\)
=>\(x=-26\)
\(x=\left(-52\right):2\)
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\(\frac{2x+3}{7}=\frac{4x-1}{15}\)
=> \(\frac{15\left(2x+3\right)}{105}=\frac{7\left(4x-1\right)}{105}\)
=> \(15\left(2x+3\right)=7\left(4x-1\right)\)
=> \(30x+45=28x-7\)
=> \(28x-30x=45+7\)
=> \(-2x=52\)
=> \(x=-26\)
Vậy......
=> \(x=52:\left(-2\right)\)
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