Question

Tìm x, biết:

\(\dfrac{1}{3}x+\dfrac{2}{5}\left(x-1\right)=0\)

Answer 1

\(\dfrac{1}{3}x+\dfrac{2}{5}\left(x-1\right)=0\)

\(\dfrac{1}{3}x+\dfrac{2}{5}x-\dfrac{2}{5}=0\\ \dfrac{11}{15}x=\dfrac{2}{5}\\ x=\dfrac{6}{11}\)

Answer 2

\(\dfrac{1}{3}x+\dfrac{2}{5}\left(x-1\right)=0\)

\(\dfrac{1}{3}x+\dfrac{2}{5}x-\dfrac{2}{5}=0\)

\(\dfrac{1}{3}x+\dfrac{2}{5}x=\dfrac{2}{5}\)

\(x.\left(\dfrac{1}{3}+\dfrac{2}{5}\right)=\dfrac{2}{5}\)

\(x.\dfrac{11}{15}=\dfrac{2}{5}\)

\(x=\dfrac{2}{5}:\dfrac{11}{15}\)

\(x=\dfrac{6}{11}\)