Tìm \(x,\) biết:
a) \(4\left|3x-1\right|+\left|x\right|-2\left|x-5\right|+7\left|x-3\right|=12\)
b) \(3\left|x+4\right|-\left|2x+1\right|-5\left|x+3\right|+\left|x+9\right|=5\)
c) \( \left|2\frac{1}{5}-x\right|+\left|x-\frac{1}{5}\right|+8\frac{1}{5}=1,2\)
d) \(2\left|x+3\frac{1}{2}\right|+\left|x\right|-3\frac{1}{2}=\left|2\frac{1}{5}-x\right|\)
Bài 1: Thu gọn
a) \(\frac{1}{5}x^4y^3-3x^4y^3\)
b) \(5x^2y^5-\frac{1}{4}x^2y^5\)
c) \(\frac{1}{7}x^2y^3.\left(-\frac{14}{3}xy^2\right)-\frac{1}{2}xy.\left(x^2y^{\text{4}}\right)\)
d) \(\left(3xy\right)^2.\left(-\frac{1}{2}x^3y^2\right)\)
e) \(-\frac{1}{4}xy^2+\frac{2}{5}x^2y+\frac{1}{2}xy^2-x^2y\)
f) \(\frac{1}{2}x^4y.\left(-\frac{2}{3}x^3y^2\right)-\frac{1}{3}x^7y^3\)
g) \(\frac{1}{2}x^2y.\left(-10x^3yz^2\right).\frac{1}{4}x^5y^3z\)
h) \(4.\left(-\frac{1}{2}x\right)^2-\frac{3}{2}x.\left(-x\right)+\frac{1}{3}x^2\)
i) \(1\frac{2}{3}x^3y.\left(\frac{-1}{2}xy^2\right)^2-\frac{5}{4}.\frac{8}{15}x^3y.\left(-\frac{1}{2}xy^2\right)^2\)
k) \(-\frac{3}{2}xy^2.\left(\frac{3}{4}x^2y\right)^2-\frac{3}{5}xy.\left(-\frac{1}{3}x^4y^3\right)+\left(-x^2y\right)^2.\left(xy\right)^2\)
n) \(-2\frac{1}{5}xy.\left(-5x\right)^2+\frac{3}{4}y.\frac{2}{3}\left(-x^3\right)-\frac{1}{9}.\left(-x\right)^3.\frac{1}{3}y\)
m) \(\left(-\frac{1}{3}xy^2\right)^2.\left(3x^2y\right)^3.\left(-\frac{5}{2}xy^2z^3\right)^{^2}\)
p) \(-2y.\left|2\right|x^4y^5.\left|-\frac{3}{4}\right|x^3y^2z\)
1.tìm x
a.\(\frac{-5}{8}+x=\frac{4}{9}\)
b.\(1^3_4.x+1^1_2=-\frac{4}{5}\)
c.\(\frac{1}{4}+\frac{3}{4}x=\frac{3}{4}\)
d.\(x.\left(\frac{1}{4}+\frac{1}{5}\right)-\left(\frac{1}{7}+\frac{1}{8}\right)=0\)
e.\(\frac{3}{35}-\left(\frac{3}{5}+x\right)=\frac{2}{7}\)
f.\(\frac{3}{7}+\frac{1}{7}:x=\frac{3}{14}\)
g.\(\left(5x-1\right)\left(2x-\frac{1}{3}\right)=0\)
Bài 1: Tìm x biết:
a, \(x.\cdot\left(\frac{1}{4}+\frac{1}{5}\right)-\left(\frac{1}{7}+\frac{1}{8}\right)=0\)
b, \(\left(5x-1\right).\left(2x-\frac{1}{3}\right)=0\)
c, \(\frac{3x+2}{5x+7}=\frac{3x-1}{5x+1}\)
d, \(\frac{x+1}{2x+1}=\frac{0,5x+2}{x+3}\)
e, \(\frac{-3}{4}-\left|\frac{4}{5}-x\right|=-1\)
tìm x biết
a) \(\frac{x-1}{x+2}=\frac{4}{5}\left(x\ne-2\right)\) b)22x+1+4x+3=264 c)\(\frac{x^2}{-8}=\frac{27}{x}\left(x\ne0\right)\) d)\(\frac{x+7}{-20}=\frac{-5}{x+7}\left(x\ne-7\right)\) e)\(\frac{x}{-8}=\frac{2}{-x^3}\left(x\ne0\right)\)
Bài 1: Thu gọn các đơn thức, xác định hệ số, phần biế, tìm bậc của các đơn thức sau:
a, \(A=\frac{2}{3}x^2y.\left(-\frac{3}{4}y\right).\left(-x^2\right)\)
b, \(C=0,12y^2.\left(-1\frac{1}{3}xy\right)^2.\left(-xy\right)^3\)
c, \(E=1,2.\left(-xy^2\right)^3.\left(-\frac{3}{5}y^2\right).\left(-0,5x^2y^3\right)^2\)
d, \(B=\frac{11}{12}\left(y^2\right)^3.\left(-\frac{1}{33}x^3\right).\left(-x\right)^2\)
e, \(D=2x^3y.\left(-\frac{1}{2}xy\right)^3.x^2y\)
f, \(F=-2\frac{1}{3}x^3z^2.\left(\frac{1}{3}xy^2z\right)^2.\left(6xyz\right)\)
1.tìm x
a.\(\left(3^1_4:x\right).\left(-1^1_4\right)=\frac{-5}{3}-\frac{5}{6}\)
b.\(\frac{-1}{4}-\frac{3}{4}:x=\frac{-11}{36}\)
c.\(\left(-1^1_5+x\right):\left(-3^3_5\right)=\frac{-7}{4}+\frac{1}{4}:\frac{1}{8}\)
d.\(\frac{-22}{15}x+\frac{1}{3}=\left|-\frac{2}{3}+\frac{1}{5}\right|\)
Bài 1: Thực hiện phép tính
a) \(2\frac{1}{2}-\frac{4}{3}+\left(\frac{-1}{3}\right)^4\)
b) \(\frac{1}{7}-\left(-\frac{3}{14}\right)+\frac{1}{2}\)
c) -12:\(\left(\frac{3}{4}-\frac{5}{6}\right)^2\)
d) \(\left(2^2:\frac{4}{3}-\frac{1}{2}\right).\frac{6}{5}-17\)
Bài 2:Tìm x biết
a) \(\frac{4}{7}-x=\frac{1}{3}\)
b) \(x-\frac{2}{3}=-\frac{6}{7}\)
c) \(\left|x-5\right|=7\)
d) \(\frac{2}{3}-1\frac{4}{15}x=\frac{-3}{5}\)
1.thực hiện phép tính
a.\(25.\left(\frac{-1}{5}\right)^3+\frac{1}{5}-2.\left(\frac{-1}{2}\right)^2-\frac{1}{2}\)
b.\(35^1_6:\left(\frac{-4}{5}\right)-46^1_6:\left(\frac{-4}{5}\right)\)
c.\(\left(\frac{-3}{4}+\frac{2}{5}\right):\frac{3}{7}+\left(\frac{3}{5}+\frac{-1}{4}\right):\frac{3}{7}\)
d.\(\frac{7}{8}:\left(\frac{2}{9}-\frac{1}{18}\right)+\frac{7}{8}.\left(\frac{1}{36}-\frac{5}{12}\right)\)
e.\(\frac{1}{6}+\frac{5}{6}.\frac{3}{2}-\frac{3}{2}+1\)
f.\(\left(-0,75-\frac{1}{4}\right):\left(-5\right)+\frac{1}{15}-\left(\frac{-1}{5}\right):\left(-3\right)\)
