Question

tìm x biết

a,\(\dfrac{2}{3}x+\dfrac{5}{7}=\dfrac{3}{10}\)

Answer 1

\(\dfrac{2}{3}x\) + \(\dfrac{5}{7}\)=\(\dfrac{3}{10}\)

=>\(\dfrac{2}{3}x\)= \(\dfrac{3}{10}\)-\(\dfrac{5}{7}\)

=>\(\dfrac{2}{3}x\)=\(\dfrac{-29}{70}\)

=> x=\(\dfrac{-29}{70}\):\(\dfrac{2}{3}\)

=> x=\(\dfrac{-87}{140}\)

Answer 2

\(a)\dfrac{2}{3}x+\dfrac{5}{7}=\dfrac{3}{10}\)

\(\dfrac{2}{3}x=\dfrac{3}{10}-\dfrac{5}{7}\)

\(\dfrac{2}{3}x=\dfrac{-29}{70}\)

\(x=\dfrac{-29}{70}:\dfrac{2}{3}\)

\(x=\dfrac{-87}{140}\)

Answer 3

\(\dfrac{2}{3}x+\dfrac{5}{7}=\dfrac{3}{10}\)

\(\Leftrightarrow\dfrac{2}{3}x=\dfrac{3}{10}-\dfrac{5}{7}\)

\(\Leftrightarrow\dfrac{2}{3}x=\dfrac{-29}{70}\)

\(\Leftrightarrow x=\dfrac{-29}{70}:2\)

\(\Leftrightarrow x=\dfrac{-29}{140}\)

Vậy x= ............