Question

tìm x
b)\(\frac{x-2}{4}=\frac{5.x}{3}\)

Answer 1

\(\frac{x-2}{4}=\frac{5x}{3}\)

\(\rightarrow3\left(x-2\right)=4.5x\)

\(\rightarrow3x-3=20x\)

\(\rightarrow3x-20x=3\)

\(\rightarrow-17x=3\)

\(\Rightarrow x=\frac{-3}{17}\)

Vậy \(x=\frac{-3}{17}\)

Nhớ tick

Answer 2

\(\frac{x-2}{4}\) =\(\frac{5x}{3}\)

3x-6=20x

-17x=6

x=\(\frac{-6}{17}\)

Answer 3

Tìm x:

b)$\frac{x-2}{4}=\; \backslash (\backslash frac\{5x\}\{3\}\backslash )$

\(\frac{x-2}{4}\) - \(\frac{5x}{3}\) = 0

\(\frac{\left(x-2\right).3}{4.3}\) - \(\frac{5x.4}{3.4}\) = 0

\(\frac{3x-6}{12}\) - \(\frac{20x}{12}\) = 0

\(\frac{3x-6-20x}{12}\) = 0

3x-6-20x = 0.12

3x-6-20x = 0

-6 = 20x -3x

-6 = 17x

x = -6 : 17

x = \(\frac{-6}{17}\)

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