Ta có: \(x^3-9x=0\)
\(\Leftrightarrow x\left(x-3\right)\left(x+3\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x=3\\x=-3\end{matrix}\right.\)
tìm x
a) x^3-9x+7x^2-63=0
b) x^3-6x^2+9x=0
Tìm x:
a) x3-9x2+27x-27=0
b) x3-25x=0
c)9x2-1=0
Tìm x
a) (2x - 3)(x^2 + 2) - 2(x + 1)^3 - 9x^2 = -5
b) 3(x - 2) - x^2 + 4 = 0
c) x^3 - 5x^2 - 10x= -50
d) x^3 + 9x= 6x^2
e) 2x^2 - 5x + 3 = 0
f) x^2 - x - 2= 0
bài 2; tìm x
a, 5x ( x - 1 ) + ( x + 17 ) = 0
b, 3x ( x - 3 ) mũ 2 - 3x ( x + 3 ) mũ 2 = 0
c, 7 - 9x + 2x mũ 2 = 0
d, 7 - 9x + 2x mũ 2 = 0
Tìm x , biết :
a) x^3 - 9x = 0
b) x^2 - 5x - 6 = 0
Câu 2.(1,5 điểm) Tìm x, biết:
a) 5x(x2 – 9) = 0. b) 3(x+3) - x2 - 3x =0. c) x2 – 9x – 10 = 0
Tìm x , biết :
a ) x ( x + 3 ) - 2x - 6 = 0
b ) 9x2 - 6x - 3 = 0
tìm X
a) x^3-5x^2-9x=0
b)(4x-3)^2-3x(3-4x)=0
1.Tìm x
a/ x(2x - 1) - 6x + 3 = 0
b/ x^2 (x + 1) - 9x - 9=0
