a) \(5-\left[x+1\right]=29\)
\(x+1=5-29\)
\(x+1=-24\)
\(x=-24-1\)
\(x=-25\)
Vậy \(x=-25\) là giá trị cần tìm
b) \(\left(-1\right)+3+\left(-5\right)+7+\left(-9\right)+........+x=600\)
\(\Rightarrow\left[\left(-1\right)+3\right]+\left[\left(-5\right)+7\right]+............+\left[-\left(x-2\right)+x\right]=600\)
\(\Rightarrow2+2+2+.......+2=600\)
\(\Rightarrow2\left(1+1+......+1\right)=600\)
\(\Rightarrow1+1+........+1=300\)
Số dấu ngoặc [] là :
\(\dfrac{x-3}{4+1}\)
\(\Rightarrow\dfrac{x-3}{4+1}=300\)
\(\Rightarrow\dfrac{x-3}{4}=299\)
\(\Rightarrow x-3=299.4\)
\(\Rightarrow x=299.4+3\)
\(\Rightarrow x=1199\)
\(5-\left|x+1\right|=29\)
\(\left|x+1\right|=5-29\)
\(\left|x+1\right|=-24\Leftrightarrow x\in\left\{\varnothing\right\}\)
