a.
\(\left(3x-2^4\right)\times7^3=2\times7^4\)
\(3x-2^4=2\times7^4\div7^3\)
\(3x-16=2\times7\)
\(3x-16=14\)
\(3x=14+16\)
\(3x=30\)
\(x=\frac{30}{3}\)
\(x=10\)
b.
\(2130-\left(x+130\right)+72=-64\)
\(2130-\left(x+130\right)=-64-72\)
\(2130-\left(x+130\right)=-136\)
\(x+130=2130+136\)
\(x+130=2266\)
\(x=2266-130\)
\(x=2136\)
c.
\(15-\left(-x+18\right)=-24\)
\(\left(-x+18\right)=15+24\)
\(-x+18=39\)
\(-x=39-18\)
\(-x=21\)
\(x=-21\)
d.
\(10-\left|x+3\right|=-4-\left(-10\right)\)
\(\left|x+3\right|=10+4-10\)
\(\left|x+3\right|=4\)
\(x+3=\pm4\)
TH1:
\(x+3=4\)
\(x=4-3\)
\(x=1\)
TH2:
\(x+3=-4\)
\(x=-4-3\)
\(x=-7\)
Vậy x = 1 hoặc x = - 7.