ta có :f(x)=\(2x^3+3x^2-6x+9\)=0
\(\Rightarrow x^2\left(2x+3\right)+3\left(2x+3\right)=0\Rightarrow\left(x^2+3\right)\left(2x+3\right)=0\)
=>\(\left[{}\begin{matrix}x^2+3=0\\2x+3=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x^2=-3\left(loai\right)\\2x=-3\Rightarrow x=\dfrac{-3}{2}\end{matrix}\right.\)
vậy đa thức có nghiệm là x= \(\dfrac{-3}{2}\)