\(5x^2-2A+4x-5=A+4x^2-6x+7\)
\(\Rightarrow5x^2+2x-5-\left(4x^2-6x+7\right)=3A\)
\(\Rightarrow5x^2+2x-5-4x^2+6x-7=3A\)
\(\Rightarrow x^2+8x-12=3A\)
\(\Rightarrow A=\dfrac{x^2+8x-12}{3}\)
Vậy \(A=\dfrac{x^2+8x-12}{3}\)
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Bình luận (3)
3A= 5x2+4x -4x2+6x -7 = x2 +10x -7
A = (x2 +10x -7)/3
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