Question

tìm các số nguyên x y z biết: ( x - y^2 + z )^2 + ( y - 2)^2 + ( z + 3)^2 = 0

Answer 1

tìm các số nguyên x,y,z biết:\(\left(x-y^2+z\right)^2+\left(y-2\right)^2+\left(z+3\right)^2=0\)

\(\Leftrightarrow\left[{}\begin{matrix}\left(x-y+z\right)^2=0\\\left(y-2\right)^2=0\\\left(z+3\right)^2=0\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x-y^2+z=0\\y-2=0\\z+3=0\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x-y^2+z=0\\y=2\\z=-3\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x-\left(2\right)^2-3=0\\y=2\\y=-3\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=7\\y=2\\z=-3\end{matrix}\right.\)

Vậy \(x=7;y=2;z=-3\)