a) \(2xy^2\left(-\dfrac{1}{3}x^2y^3\right)^3=2xy^2\left(-\dfrac{1}{27}x^6y^9\right)=-\dfrac{2}{27}x^7y^{11}\)
b) \(\left(-\dfrac{1}{2}x^2y\right)\left(-\dfrac{2}{3}x^2y^3\right)^3=\left(-\dfrac{1}{2}x^2y\right)\left(-\dfrac{8}{27}x^6y^9\right)=\dfrac{4}{27}x^8y^{10}\)