Question

So sanh AvaB

A=\(\dfrac{20}{39}+\dfrac{22}{27}+\dfrac{18}{43},B=\dfrac{14}{39}+\dfrac{22}{29}+\dfrac{18}{41}\)

Answer 1

Ta có: \(\dfrac{20}{39}>\dfrac{20}{41}>\dfrac{18}{41}\left(1\right)\)

\(\dfrac{22}{27}>\dfrac{22}{29}\left(2\right)\)

\(\dfrac{18}{43}=1-\dfrac{25}{43};\dfrac{14}{39}=1-\dfrac{25}{39}\)

Vì \(\dfrac{25}{43}< \dfrac{25}{39}\Rightarrow1-\dfrac{25}{43}>1-\dfrac{25}{39}\Rightarrow\dfrac{18}{43}>\dfrac{14}{39}\left(3\right)\)

Từ \(\left(1\right);\left(2\right);\left(3\right)\) ta suy ra : A>B