Question

So sánh: A= \(\sqrt{2}\)+\(\sqrt{6}\)+\(\sqrt{12}\)+\(\sqrt{20}\)+\(\sqrt{30}\)+\(\sqrt{42}\)

và B=24

Answer 1

ta có A=1+2+3+4+5+6=\(\sqrt{1}\)+\(\sqrt{4}\)+\(\sqrt{9}\)+\(\sqrt{16}\)+\(\sqrt{25}\)+\(\sqrt{36}\)

Ta thấy \(\sqrt{1}\)<\(\sqrt{2}\)

\(\sqrt{4}\)<\(\sqrt{6}\)

.............

\(\sqrt{36}\)<\(\sqrt{42}\)

có gì sai thì sửa nhé

=>\(\sqrt{1}\)+\(\sqrt{4}\)+\(\sqrt{9}\)+\(\sqrt{16}\)+\(\sqrt{25}\)+\(\sqrt{36}\)<\(\sqrt{2}\)+\(\sqrt{6}\)+\(\sqrt{12}\)+\(\sqrt{20}\)+\(\sqrt{30}\)+\(\sqrt{42}\)

=>B<A hay A>B

Answer 2

đầu tiên là B= chứ k phải A= đâu bạn sửa lại đi

Answer 3

Ta có B=1+2+3+4+5+6=\(\sqrt{1}\)+\(\sqrt{4}\)+\(\sqrt{9}+\sqrt{16}+\sqrt{25}+\sqrt{36}\)

Ta thấy \(\sqrt{1}< \sqrt{2}\)

\(\sqrt{4}< \sqrt{6}\)

..........

\(\sqrt{36}< \sqrt{42}\)

\(\Rightarrow\)\(\sqrt{1}+\sqrt{4}+\sqrt{9}+\sqrt{16}+\sqrt{25}+\sqrt{36}\)<\(\sqrt{2}\)+\(\sqrt{6}\)+\(\sqrt{12}\)+\(\sqrt{20}\)+\(\sqrt{30}\)+\(\sqrt{42}\)

\(\Rightarrow\)B<A hay A>B