a) \(A=\dfrac{6.9-2.17}{63.3-119}=\dfrac{2.3.9-2.17}{7.9.3-7.17}=\dfrac{2.27-2.17}{7.27-2.17}=\dfrac{2\left(27-17\right)}{7\left(27-17\right)}=\dfrac{2.10}{7.10}=\dfrac{2}{7}\)
b)\(B=\dfrac{1989.1990+3978}{1992.1991-3984}=\dfrac{1989.1990+2.1989}{1992.1991-2.1992}=\dfrac{1989.\left(1990+2\right)}{1992.\left(1991-2\right)}=\dfrac{1989.1992}{1992.1989}=1\)