1.Tính :
a) 1253 : 57
b) \(\left(\dfrac{2}{7}\right)^{18}:\left(\dfrac{4}{49}\right)^5:\left(\dfrac{8}{343}\right)^2\)
c) 3 - \(\left(-\dfrac{7}{9}\right)^0+\left(\dfrac{1}{3}\right)^5.3^5\)
d) \(\dfrac{45^{10}.5^{20}}{75^{15}}\)
Thực hiện phép tính:
\(A=\dfrac{2^{12}.3^5-4^6.9^2}{\left(2^2.3\right)^6+8^4.3^5}-\dfrac{5^{10}.7^3-25^5.49^2}{\left(125.7\right)^3+5^9.14^3}\)
\(B=\dfrac{1-\dfrac{1}{\sqrt{49}}+\dfrac{1}{49}-\dfrac{1}{\left(7\sqrt{7}\right)^2}}{\dfrac{\sqrt{64}}{2}-\dfrac{4}{7}+\dfrac{2^2}{7^2}-\dfrac{4}{343}}\)
Thực hiện phép tính
a, A = \(\left(\dfrac{1}{4\times9}+\dfrac{1}{9\times14}+\dfrac{1}{14\times19}+....+\dfrac{1}{44\times49}\right)\times\dfrac{1-3-5-7-....-49}{89}\)
b, B = \(\dfrac{2^{12}\times3^5-4^6\times9^2}{\left(2^2\times3\right)^6+8^4\times3^5}-\dfrac{5^{10}\times7^3-25^5\times49^2}{\left(125\times7\right)^3-5^9\times14^3}\)
Rút gọn A=\(\dfrac{7^{48}\cdot5^{30}\cdot2^8-5^{30}\cdot7^{49}\cdot2^{10}}{5^{29}\cdot2^8\cdot7^{48}}\)
Rút gọn:
a) \(\dfrac{9^3}{\left(3^4-3^3\right)^2}\)
b)\(\dfrac{\left(5^4-5^3\right)^2}{1255}\)
c)\(\dfrac{32^5.81^4}{16^5.27^5}\)
d)\(\dfrac{20^{10}.81^4}{19^2.75^5}\)
e)\(\dfrac{23^3-5^5}{125}\)
f)\(\dfrac{16^4-8^5}{48}\)
a. 0,5.\(\sqrt{100}\)-\(\sqrt{\dfrac{1}{49}}\)+\(\sqrt{225}\)
b. 6.\(\left(-\dfrac{2}{3}\right)+12.\left(-\dfrac{2}{3}\right)^2+18\left(-\dfrac{2}{3}\right)^3\)
c. \(\left(2,5+3,75-\dfrac{5}{8}+\dfrac{10}{15}\right)\): \(\left(8,5+12,75-\dfrac{17}{8}+\dfrac{34}{15}\right)\)
Tính hợp lí nếu có thể
a) \(\left(\dfrac{5}{7}-\dfrac{7}{5}\right)-\left[\dfrac{1}{2}-\left(-\dfrac{2}{7}-\dfrac{1}{10}\right)\right]\)
b) \(\dfrac{2}{15}:\left(-5\dfrac{4}{5}\right).2\dfrac{5}{12}+\sqrt{1\dfrac{9}{16}}:\left(-\dfrac{3}{4}\right)\)
thực hiên phép tính :
a, \(\left(3^2\right)^2-\left(2^3\right)^2-\left(-5^2\right)^2\)
b, \(2^3+3.\left(-\dfrac{1}{2}\right)^0-\left(\dfrac{1}{2}\right)^2.4+\left(\left(-2\right)^2:\dfrac{1}{2}\right):8\)
c, \(\left(4.2^5\right):\left(2^3.\dfrac{1}{16}\right)\)
d, \(A=\dfrac{2^{12}.3^5-4^6.9^2}{\left(2^2.3\right)^6+8^4.3^5}-\dfrac{5^{10}.7^3-25^5.49^2}{\left(125.7\right)^3+5^9.14^3}\)
\(\dfrac{2^{12}\cdot3^5-4^6\cdot9^2}{\left(2^3\cdot3\right)+8^4\cdot3^5}-\dfrac{5^{10}\cdot7^3-25^5\cdot49^2}{\left(125\cdot7\right)^3+5^9\cdot14^3}\) .Tính tổng
