tim x
-2x(6x-2)+3x(4x-7)=8
(7x-2)(2x+3)-(3x-5)(4x+6)=2x2-5
+(-2x+3)-6x(3x-4)=-22x2+7x
1)6x-8=3x+1
2)12-10x=25-30x
3)3(2x+3)-2(4x-5)=10x+21
4)5(5x-3)-3(2x-4)11-5x
5)4(2-3x)-5(1-2x)=4-6x
6)8(4x-3)-3(2-3x)=13-40x
7)10x-5(1-4x)=5x-11
8)-3(3-4x)-5(4-3x)=12x-50
9)-2(20x-3)-3(4x-5)=9-2(2x-3)
10)-5(2-3x)+3(5-2x)=3x+3(3-5x)
Rút gọn
(2x+9)(4x^2-2xy+y^2)-(2x-y)(4x^2+2xy+y^2)
rut gon
a,3x(2x-7)-3x(4x-5)
b,(-7x+8)(-2x+3)-7x(2x-4)
c,(2x-3)(3x2-2x+4)-(2x-3)(3x+4)
d,(-2+7)(3x-6)-(4x-5)(2x-6)
tìm x:
\(a,\frac{x}{2}+\frac{2x}{3}+\frac{x+1}{4}+\frac{2x+1}{6}=\frac{8}{3}\)
\(b,\frac{3}{2x+1}+\frac{10}{4x+2}-\frac{6}{6x-3}=\frac{12}{26}\)
Bất đẳng thức
1.Thu gọn
A=(4x-6) - |-10 + 5x|
B=|x-5| - (7-4x) - |-12+2x|
2.Tìm x(bằng cách lập bảng xét dấu)
(x^2 + 3)(2x-6) bé hơn hoặc bằng 0
1) 4x-(2x-5)=21
2) 14x+5=8x+10
3) 15+5x=3x+30
4) 2x-5=15-3x
5) 2(3x+5)+3(x+1)=6x+20
6) 4(x-3)+5(x-3)=18
Bài 1 : Tìm x
a) 2x + 1 phần 7 = 1 phần 3
b) 3(x - 1 phần 2) = 4 phần 9
c) ( x - 5)2 + 4 = 68
d) (|x|- 1 phần 2 ) (2x + 3 phần 2) = 0
e) 5x + 2 = 3x + 8
f) 26 - (5 - 2x) = 27
g) ( 4x - 8 ) - ( 2x - 6 ) = 4
h) (x + 3)3 ÷ 3 - 1 = - 10
1) 3(x-5)(2x+9)+3x-15=0
2) (x2-16)(12-4x)=0
3) (9-x2)(4x-8)=0
4) (8-x3)(5x-125)=0
5) 4x=8
