Question

Phân tích đa thức sau thành nhâ tử: (3x-11)(4x^2-1)-(9x-3)(2x-1)^2

Answer 1

Sửa đề: \(\left(3x-1\right)\left(4x^2-1\right)-\left(9x-3\right)\left(2x-1\right)^2\)

\(=\left(3x-1\right)\left(2x-1\right)\left(2x+1\right)-3\left(3x-1\right)\left(2x-1\right)^2\)

\(=\left(3x-1\right)\left(2x-1\right)\left(2x+1-6x+3\right)\)

\(=\left(3x-1\right)\left(2x-1\right)\left(-4x+4\right)\)

\(=-4\left(3x-1\right)\left(2x-1\right)\left(x-1\right)\)

Answer 2

Sửa Đề 

\(=\left(3x-1\right)\left(2x-1\right)\left(2x+1\right)-3\left(3x-1\right)\left(2x-1\right)^2\\ =\left(3x-1\right)\left(2x-1\right)\left(2x+1-6x+3\right)\\ =\left(3x-1\right)\left(2x-1\right)\left(-4x+4\right)\\ =4\left(3x-1\right)\left(2x-1\right)\left(-x+1\right)\)

Answer 3

\(=(3x-11)(2x-1)(2x+1)-(9x-3)(2x-1)(2x-1)\)

\(=(2x-1)[(3x-11)(2x+1)-(9x-3)(2x-1)]\)

\(=(2x-1)[6x^2-10x-11-(18x^2-4x+3)]\)

\(=-(2x-1)(12x^2+6x+14)\)