\(1-\frac{2010}{2010}=0\Rightarrow\left(1-\frac{1}{2010}\right)\left(1-\frac{2}{2010}\right)....\left(1-\frac{2012}{2010}\right)=0\)
Bài 1: Tính a) \(\left(\frac{11}{12}:\frac{44}{16}\right)\cdot\left(\frac{-1}{3}+\frac{1}{2}\right)\) b) \(\frac{\left(-5^2\right)\cdot\left(-5\right)^3\cdot16}{5^4\cdot\left(-2\right)^4}\) c) \(7,5:\left(\frac{-5}{3}\right)+2\frac{1}{2}:\left(\frac{-5}{3}\right)\)d) \(\left(\frac{-1}{2}+\frac{1}{3}\right)\cdot\frac{4}{5}+\left(\frac{2}{3}+\frac{1}{2}\right):\frac{4}{5}\)
1.tính tổng
a. A=\(\left(1-\frac{1}{2}\right).\left(1-\frac{1}{3}\right).\left(1-\frac{1}{4}\right).....\left(1-\frac{1}{20}\right)\)
b. B=\(\left(1-\frac{1}{2010}\right).\left(1-\frac{2}{2010}\right).\left(1-\frac{3}{2010}\right).....\left(1-\frac{2011}{2010}\right)\)
Bài 1:
a)\(\frac{5}{6}\)-\(\frac{2}{3}+\frac{1}{4}\) b)\(1\frac{11}{12}-\frac{5}{12}\cdot\left(\frac{4}{5}-\frac{1}{10}\right):\frac{-5}{12}\)
Bài 2:
a) \(\frac{1}{2}\cdot x-\frac{2}{5}=\frac{1}{5}\) b)\(\left(1-2\cdot x\right)\cdot\frac{4}{3}=\left(-2\right)^3\)
Bài 1: Tìm x a) \(\frac{1}{7}\cdot\left|x\right|-\frac{4}{5}=\frac{1}{5}\) b) \(\left(\frac{3}{4}-x\right)^3=-27\) c) \(\frac{x-1}{-2}=\frac{-8}{x-1}\) d) \(\left|2x-3\right|+4\cdot\left(-5\right)^2=101\)
\(a,\frac{16}{15}\cdot\frac{-5}{14}\cdot\frac{54}{24}\cdot\frac{56}{21}\)
\(b,5\cdot\frac{7}{5}\) \(c,\frac{1}{7}\cdot\frac{5}{9}+\frac{5}{9}\cdot\frac{1}{7}+\frac{5}{9}\cdot\frac{3}{7}\)
\(d,4\cdot11\cdot\frac{3}{4}\cdot\frac{9}{121}\)
\(e,\frac{3}{4}\cdot\frac{16}{9}-\frac{7}{5}:\frac{-21}{20}\)
\(g,2\frac{1}{3}-\frac{1}{3}\cdot\left[\frac{-3}{2}+\left(\frac{2}{3}+0,4\cdot5\right)\right]\)
4,Tìm x biết
a,\(\frac{-2}{3}\cdot x+\frac{1}{5}=\frac{3}{10}\)
b,\(\frac{2}{3}\cdot x-\frac{3}{2}\cdot x=\frac{5}{12}\)
c,\(\left(4,5-2x\right)\cdot\left(-1\frac{4}{7}\right)=\frac{11}{14}\)
d,\(\frac{1}{4}+\frac{1}{3}:3x=-5\)
e,\(\left(2\frac{4}{5}x-50\right):\frac{2}{3}=51\)
g,\(|4x-1|=\left(-3^2\right)\)
h,\(|x+70|=2\frac{1}{5}\)
i,\(\left(x-1^3\right)=125\)
k,\(\left(x+\frac{1}{2}\right)\cdot\left(\frac{2}{3}-2x\right)=0\)
Giúp mình nhé!!!
1/S=\(\left(1+\dfrac{1}{2}\right)\cdot\left(1+\dfrac{1}{3}\right)\cdot\left(1+\dfrac{1}{4}\right)\cdot...\cdot\left(1+\dfrac{1}{100}\right)\)
2/B=\(\left(1-\dfrac{1}{2}\right)\cdot\left(1-\dfrac{1}{3}\right)\cdot\left(1-\dfrac{1}{4}\right)\cdot...\cdot\left(1-\dfrac{1}{2007}\right)\)
3/C=\(\dfrac{2^2}{1\cdot3}\cdot\dfrac{3^2}{2\cdot4}\cdot\dfrac{4^2}{3\cdot5}\cdot...\cdot\dfrac{100^2}{99\cdot101}\)
2,Thực hiện phép tính(tính nhanh nếu có thể)
a,\(\frac{2}{3}+\frac{1}{3}\cdot\left(-\frac{2}{5}\right)\)
b,\(0,75\cdot1\frac{7}{9}-1\frac{2}{5}:\frac{-21}{20}\)
c,\(\frac{-2}{17}+\frac{15}{23}+\frac{15}{-17}-\frac{-4}{19}+\frac{8}{23}\)
d,\(2019^0\cdot\left(6-2\frac{4}{5}\right)\cdot3\frac{1}{8}-1\frac{3}{5}:25\)phần trăm
e,\(\left(\frac{7}{8}-\frac{1}{2}\right)\cdot2\frac{2}{3}-\frac{3}{7}\cdot\left(2,5^2\right)\)
TÍNH GIÁ TRỊ BIỂU THỨC:\(\left(1+\dfrac{2}{3}\right)\cdot\left(1+\dfrac{2}{4}\right)\cdot\left(1+\dfrac{2}{5}\right)\cdot...\cdot\left(1+\dfrac{2}{97}\right)\cdot\left(1+\dfrac{2}{98}\right)\)
