Question

Giúp mình với ạ mình cảm ơn nhiều

Answer 1

Bài 1: 

a: \(\dfrac{13\sqrt{2}-4\sqrt{6}}{24-4\sqrt{3}}=\dfrac{\sqrt{2}\left(13-4\sqrt{3}\right)}{4\sqrt{3}\left(2\sqrt{3}-1\right)}=\dfrac{\sqrt{2}\left(2\sqrt{3}-1\right)}{4\sqrt{3}}=\dfrac{\sqrt{6}\left(2\sqrt{3}-1\right)}{12}\)

b: \(\dfrac{\sqrt{3-2\sqrt{2}}}{\sqrt{17-12\sqrt{2}}}=\dfrac{\sqrt{2}-1}{3-2\sqrt{2}}=\sqrt{2}+1\)