4) \(\left|\dfrac{5}{18}-x\right|-\dfrac{7}{24}=0\)
\(\Leftrightarrow\left|\dfrac{5}{18}-x\right|=\dfrac{7}{24}\)
\(\Leftrightarrow\left[{}\begin{matrix}\dfrac{5}{18}-x=\dfrac{7}{24}\\\dfrac{5}{18}-x=-\dfrac{7}{24}\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=-\dfrac{1}{72}\\x=\dfrac{41}{72}\end{matrix}\right.\)
b) \(\dfrac{2}{5}-\left|\dfrac{1}{2}-x\right|=6\)
\(\Leftrightarrow\left|\dfrac{1}{2}-x\right|=-\dfrac{28}{5}\)( vô lý do \(\left|\dfrac{1}{2}-x\right|\ge0\forall x\))
Vậy \(S=\varnothing\)